a potential difference of 200 /__ 30 deg is applied to two circuits connected in parallel. the current in the respective branches are 20 /__ 60 deg and 40 /__ 3 deg. Find:

1) Active power consumed by each branch and whole circuit

2) Reactive power in each branch and in the whole circuit

Additional Details

i thought it would b solved in the following way. is it correct?

since power =VI

for active power in branch 1

I=I(1) cos 60

V= v cos 30

for reactive power in branch 1

I= I (1) sin 60

V=v sin 30

for total active power

I=i(1)cos60+i(2)cos3

V=vcos 30Similar Threads:

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