Close
Login to Your Account
Faadooengineers

Results 1 to 13 of 13

Thread: F! Contest - Master-Mind of the DAY: Day 5

  1. #1

    Favorite 32 F! Contest - Master-Mind of the DAY: Day 5

    Hey FaaDoOs!!

    This is the Fifth thread for master mind of the day...

    Are you planning to become an MBA? Or wanna take the GRE route? Or are you tired of studying and wanna jump into a job straight after your engineering??

    Whatever be your interest, one thing is for sure – you are going to come across a lot of ‘aptitude’ questions along your way to realizing your dreams!

    More details HERE

    Match your wits against one daily puzzler of a question! And who knows if you are the first one to crack it, you might just be the winner of a Rs.100 mobile recharge!!


    Here's the Question for DAY 5 of Master mind of the day--

    Q1.) We have 3 glasses X, Y, Z having a mixture of juice and vodka. The concentration of juice in every glass is d1, d2, d3 respectively.



    When a part of glass X is replaced with the mixture in glass Y, then concentration of juice in the final mixture is less than d1.

    When glass Y & Z are mixed in ratio 1:1, then the quantity of juice in the final mixture is twice than the quantity of juice in the glass Y. Which glass is having the mixture of maximum concentration of juice? Also, which glass is having the mixture of minimum concentration of juice?

    Correct Answer will win FREE Mobile Recharge worth Rs.100!!!

    Entries will be accepted till 7PM, 2nd Dec. 2011!




  2. #2

    Re: F! Contest - Master-Mind of the DAY: Day 5

    glass Y is having minimum concentration of juice

  3. #3

    Re: F! Contest - Master-Mind of the DAY: Day 5

    glass Y is having minimum concentration of juice and glass Z is having maximum concentration of juice

  4. #4

    Re: F! Contest - Master-Mind of the DAY: Day 5

    it's not possible to find the glass which has maximum concentration of juice as the relation b/w X and Z is not known..and Y has minimum concentration of juice.

  5. #5

    Re: F! Contest - Master-Mind of the DAY: Day 5

    exactly the same problem is with me..
    if we assume that full quantities of Y and Z are mixed then surely X>Y=Z
    or if we assume quantities in this case also as concentration then.. only information that can be gathered from above will be..
    X>Y and Z>Y

  6. #6

    Re: F! Contest - Master-Mind of the DAY: Day 5

    Question 1 : X maximum
    Y = Z mimimum

  7. #7

    Re: F! Contest - Master-Mind of the DAY: Day 5

    X is having maximum concentration
    Both Y and Z having same concentration and is minimum

  8. #8

    Re: F! Contest - Master-Mind of the DAY: Day 5

    X has the maximum concentration of juice, while concentration of juice in Y And Z are same.

  9. #9

    Re: F! Contest - Master-Mind of the DAY: Day 5

    maximum concentration is of X...... Y and Z have same concentration.....(X>Y & Y=Z)

  10. #10

    Re: F! Contest - Master-Mind of the DAY: Day 5

    admin plz clear the question.. language is not perfect..

  11. #11

    Re: F! Contest - Master-Mind of the DAY: Day 5

    I think Z is having the maximum conc. of juice and Y is minimum in concentration of the juice.......

  12. #12

    Re: F! Contest - Master-Mind of the DAY: Day 5

    Q1 : X maximum
    Y = Z mimimum

  13. #13

    Re: F! Contest - Master-Mind of the DAY: Day 5

    TIME UP!!!

    The correct Answers are:

    1. Maximum Concentration - Vessel Z

    2. Minimum Concentration - Cannot be determined!!

    [MENTION=38990]ashwanisingh835[/MENTION] came closest to the right answer, thus WINS DAY 5 of MASTER-MIND of the Day for DAY 5!!!

    He takes home a cool Rs.100 Mobile Recharge..!!

    Thread closed
    !

Tags for this Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  

Share anywhere and get download.

50%