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THE OSCULATING CIRCLE

At T1 the transition has the same radius as the straight T1I, that is,∞, but diverges from it at a constant rate. Exactly the same condition exists at P with the osculating circle, that is, the transition has the same radius as the osculating circle, r, but diverges from it at a constant rate. Thus if chords T1t = Pa = Pb = l, then: Read this topic
  1. #1
    FaaDoO-Administrator FaaDoO-Engineer's Avatar
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    Article: And We Are Back...!

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    • #2
      Active FaaDoO Engineer [FE].Zatak's Avatar
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      nice pictures

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      Fuchcha FaaDoO Engineer
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      i congratulate to each and every person who have work hard to bring this beautiful website to this level.and i think this website will rock in future.:ignat_02::ignat_02::ignat_02::ignat_02::ignat_02::zagruz:

    • #4
      Fuchcha FaaDoO Engineer Ankit Gupta's Avatar
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      This is really a proud moment for the Faadoo Team
      Congo Team !!!
      Really appreciate the work u people are doing.

      Keep working Like this.....bring in more n more new stuffs
      so that Faadoo can crash more n more servers like this.

      Good Luck for ur Future.