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Thread: Article: And We Are Back...!

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THE OSCULATING CIRCLE

At T1 the transition has the same radius as the straight T1I, that is,∞, but diverges from it at a constant rate. Exactly the same condition exists at P with the osculating circle, that is, the transition has the same radius as the osculating circle, r, but diverges from it at a constant rate. Thus if chords T1t = Pa = Pb = l, then: Read this topic
  1. 26th January 2011 , 01:09 PM #1
    FaaDoO-Engineer
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    Article: And We Are Back...!

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    • 26th January 2011 , 02:07 PM #2
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      nice pictures
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    • 27th January 2011 , 09:50 PM #3
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      i congratulate to each and every person who have work hard to bring this beautiful website to this level.and i think this website will rock in future.:ignat_02::ignat_02::ignat_02::ignat_02::ignat_02::zagruz:
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    • 28th January 2011 , 12:14 PM #4
      Ankit Gupta
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      This is really a proud moment for the Faadoo Team
      Congo Team !!!
      Really appreciate the work u people are doing.

      Keep working Like this.....bring in more n more new stuffs
      so that Faadoo can crash more n more servers like this.

      Good Luck for ur Future.
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