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# Thread: F! Contest - Master-Mind of the DAY: Day 8

1. ## F! Contest - Master-Mind of the DAY: Day 8

This is the Eighth thread for master mind of the day...

Are you planning to become an MBA? Or wanna take the GRE route? Or are you tired of studying and wanna jump into a job straight after your engineering??

Whatever be your interest, one thing is for sure – you are going to come across a lot of ‘aptitude’ questions along your way to realizing your dreams!
More details HERE

Match your wits against one daily puzzler of a question! And who knows if you are the first one to crack it, you might just be the winner of a Rs.100 mobile recharge!!

Here's the First Question for DAY 8 of Master mind of the day--

Q1.) Ram was born 30 years after his father was born. His sister, Avanti was born 25 years later after their mother was born. At present the average age of the family is 26.25 years.
Avanti will get married in 4 years from now and will leave the family.

So, the average age of the family will be 107/3 years.
What will be the age of Ram’s father?

Q2.)
Amber has to weigh 6 different packets. He weighs them four at a time, weighing all possible combinations of 6 packets. The average weight of all the weighing combination is found to be 500 gms.
What is the combined weight of all the six packets?

Correct Answer will win FREE Mobile Recharge worth Rs.100!!!

Entries will be accepted till 7PM, 6th Dec. 2011!

2. ## Re: F! Contest - Master-Mind of the DAY: Day 8

The age of his Ram's father is 45. Mother is 35. And of Ram is 15, and his sister is 10.

3. ## Re: F! Contest - Master-Mind of the DAY: Day 8

ram's father will be of 49 years at the time of his daughter's marraige.

4. ## Re: F! Contest - Master-Mind of the DAY: Day 8

Calculation :

Let Ram's father age presently is X and that of Ram's mother is Y.
Age of Ram = X-30
Age of Ram's Sisters's = Y-25

So, By the problem : Avg of their ages is 26.25

So : 2x+2y-55/4=26.25

Solving : x+y=80

After 4 years, Ram's sister will leave.

So sum of the ages of Ram,his father and mother = x+(x-30)+y+(4*3)

By the problem : 2x-30+y+12=107
so, 2x-y=125

Solving the 2 eqns :

x=45,y=35

---------- Post added at 07:10 PM ---------- Previous post was at 07:08 PM ----------

So,after age of Ram's father is 49 years.

5. ## Re: F! Contest - Master-Mind of the DAY: Day 8

I think the age of father cannot be determined.......

6. ## Re: F! Contest - Master-Mind of the DAY: Day 8

45 yrs....Age of Ram's father will be 45 years

7. ## Re: F! Contest - Master-Mind of the DAY: Day 8

Questtion 1 : 45 years

9. ## Re: F! Contest - Master-Mind of the DAY: Day 8

Ram's age is 45 at time of avanti's marriage and mothers age is 35

10. ## Re: F! Contest - Master-Mind of the DAY: Day 8

Ram's father is 45. Mother is 35. And of Ram is 15, and his sister is 10
At his daughter's marriage Ram's father will be 49 year old.

11. ## Re: F! Contest - Master-Mind of the DAY: Day 8

Let the age of the father at present=x
The age of the mother at present=y
Age of the son at present=x-30
Age of the daughter at present=y-25

Given the presen average of their ages=26.25
=> (x+y+(x-30)+(y-25))/4=26.25
=> 2x+2y-55=105
=> 2(x+y)=160
=> x+y=80

After 4 years daughter leaves the family, now the given average is 107/3
=>((x+4)+(y+4)+(x-30+4))/3=107/3
=> 2x+y-18=107
=> 2x+y=125

Solving both equations we get present age of the father x=45
So the age of father at the time of his daughters marriage=49

12. ## Re: F! Contest - Master-Mind of the DAY: Day 8

father's present age = 45.
at time of her daughter marriage = 49

13. ## Re: F! Contest - Master-Mind of the DAY: Day 8

The Combined weight of all the 6 packets is 3000 gms.

4 packets can be chosen out of 6 in 4C6 ways, i.e. 15 ways.

Now since avg. for each combination is 500 gms, we can say that Combined weight of each combination = 2000 gms.(500*4)

Now, since there are 15 combinations, total weight = 2000*15 gms

Now,each combination has 4 packets, total 15 combinations..so total number of packets=60, with each of the packets repeated in multiple combinations. Since there are 6 packets, Each packet features in 10 combinations . It can also be found like this : Lets consider 6 packets. A,B,C,D,E,F. If we consider A to be present in each combination,the rest 3 packets to complete the set of 4 can be selected in 5C3 ways= 10 ways.

So we can say, 10(A+B+C+D+E+F)=2000*15
so, A+B+C+D+E+F = 2000*15/10 = 3000 gms.

14. ## Re: F! Contest - Master-Mind of the DAY: Day 8

THE COMBINED WEIGHT OF 6 PACKETS IS 750gms.

15. ## Re: F! Contest - Master-Mind of the DAY: Day 8

Awww.....

No Winner for Master Mind of the Day- DAY 8